![]() ![]() Repeat the experiment for two more times.Make a separate table for the second given body similar to Tables A and B.Repeat the experiment in the same manner as done for the measurement for the apparent loss of weight of brass bob in tap water and salty water.Take a different solid body such as a metallic rectangular block given by your teacher.(B) Measurement for the apparent loss in weight of second solid body: Again take the same solid body (i.e., brass bob) and repeat the steps from (1) to (8) with strongly salty water.ġ2.Tabulate your observations in Table B. Take a beaker of capacity 500 mL and pour 300 mL of tap water into it.ġ0.Dissolve the common salt (known amount) by stirring with the help of a glass rod till the saturation state of the solution.ġ1. Repeat the above steps two more times with the same brass bob after drying up completely.Therefore, the weight of displaced water would be equal to the loss of weight in the brass bob. The weight of liquid displaced is equal to the upthrust. Find the weight of displaced water by subtracting the reading of step (2) from step (6).Weigh the beaker containing displaced water which is collected from the overflow can while immersing the bob in it completely.This will give you the weight of the brass bob in tap water. Note down the new position of pointer of the spring balance.Now, allow the bob to immerse completely in water in overflow’ can.Set the spring balance, overflow can with tap water and beaker as shown in Fig 3.2.Weigh the empty beakers using spring balance.Measure the weight of a solid, say a metallic ball in air by using spring balance as shown in Fig 3.1 and as per procedure explained in Experiment 2 of Term II.(A) Measurement for the apparent loss in weight of brass bob: Loss in weight = Weight of body in air – Weight of body immersed in water The loss in weight of a body is due to the presence of upthrust which is equal to the weight of liquid displaced. The loss in weight is equal to the weight of liquid displaced by the body. You can also Download Class 9 Science Notes PDF to help you to revise complete Syllabus and score more marks in your examinations.Īccording to Archimedes’ principle, when a body is immersed in a liquid, completely or partially, it loses its weight. strongly salty water, with the weight of water displaced by it by taking at least two different solids.Ī spring balance, a clamp stand, two different solids, such as metallic brass bob and rectangular block, overflow can, tap water, strongly salty water, a strong thread and two empty beakers.To establish the relation between the loss in weight of solid when fully immersed in CBSE Class 9 Science Practical Skills – Archimedes’ Principle
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